Question

A bubble of air is underwater at temperature ${15}^{\circ }C$ and the pressure $1.5$ bar. If the bubble rises to the surface where the temperature is ${25}^{\circ }C$ and the pressure is $1.0$ bar, what will happen to the volume of the bubble?

• A. Volume will become greater by a factor of $1.6$
• B. Volume will become greater by a factor of $1.1$
• C. Volume will become smaller by a factor of $0.70$
• D. Volume will become greater by a factor of $2.9$

Answer 1

The correct option is A Volume will become greater by a factor of $1.6$

$\because \frac{p_1{V}_1}{T_1}=\frac{p_2{V}_2}{T_2}$ (By ideal gas equation)

or $\frac{1.5\times V_1}{288}=\frac{1\times V_2}{298}$

$\therefore V_2=1.55V_1$

i.e., volume of bubble will be almost $1.6$ times to initial volume of bubble.