A bucket containing water is whirred in a vertical circle at arm's length. find the minimum speed at the top to ensure that no- water spills out then(given=r=0.75m)

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Solution

To complete vertical circle= $V_{m i n}$
applying conservation of M.E
$V_{i} + k_{i} = V_{f} + K_{f}$
$\frac{1}{2} m V^{2} + 0 = 2 m g r + \frac{1}{2} m g r$
$\frac{m v^{2}}{2} = \frac{5}{2} m g V$
$V = \sqrt{5 g v}$
$V = \sqrt{50 \times \frac{75}{100}}$
$v = \sqrt{\frac{75}{2}} = \sqrt[5]{\frac{3}{2}} m / s e c$ .

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A bucket containing water is whirred in a vertical circle at arm's length. find the minimum speed at the top to ensure that no- water spills out then(given=r=0.75m)(given=r=0.75m)

To complete vertical circle=Vminapplying conservation of M.EVi+ki=Vf+Kf12mV2+0=2mgr+12mgrmv22=52mgVV=√5gvV=√50×75100v=√752=5√32m/sec.

A bucket containing water is whirred in a vertical circle at arm's length. find the minimum speed at the top to ensure that no- water spills out then(given=r=0.75m)