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Standard XII

Chemistry

Acidic Buffer Action

A buffer solu...

Question

A buffer solution of $p H = 5.74$ is to be prepared using $C H_{3} C O O H$ and $C H_{3} C O O N a$ . Find the concentration of sodium acetate to be added to $0.01 M$ solution of $C H_{3} C O O H$
$K_{a} (C H_{3} C O O H) = 1.8 \times 10^{- 5}$
Take $l o g (1.8) = 0.26$

0.1 M

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0.5 M

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1 M

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1.5 M

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Solution

The correct option is A 0.1 M
$p K_{a} = - l o g (K_{a}) p K_{a} = - l o g (1.8 \times 10^{- 5}) = (5 - 0.26) p K_{a} = 4.74$
$p H = p K_{a} + l o g \frac{[s a l t]}{[a c i d]} p H = p K_{a} + l o g (\frac{[C H_{3} C O O N a]}{[C H_{3} C O O H]}) 5.74 = 4.74 + l o g \frac{[C H_{3} C O O N a]}{0.01} 1 = l o g \frac{[C H_{3} C O O N a]}{0.01} 10^{1} = \frac{[C H_{3} C O O N a]}{0.01} [C H_{3} C O O N a] = 0.1 M$

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Similar questions

Q. A buffer solution of

p H = 5.74

is to be prepared using

C H_{3} C O O H

and

C H_{3} C O O N a

. Find the concentration of sodium acetate to be added to

0.01 M

solution of

C H_{3} C O O H

K_{a} (C H_{3} C O O H) = 1.8 \times 10^{- 5}

Take

l o g (1.8) = 0.26

Q. A buffer solution of

p H = 4

is to be prepared, using

C H_{3} C O O H

and

C H_{3} C O O N a .

The concentration of acetic acid and sodium acetate are

\frac{1}{10} M

and

x M

. How much will the

p H

be if

1.5 L

H_{2} O

is added to above buffer ?

K_{a} (C H_{3} C O O H) = 4.7447

Q. Calculate the pH of 1 M

C H_{3} C O O N a

solution.

(K_{a} = 1.8 \times 10^{- 5})

Take

l o g (1.8) = 0.26

Q. Suppose it is required to make a buffer solution of pH = 4, using acetic acid and sodium acetate.
How many grams of sodium acetate is to be added to one litre of

\frac{N}{10}

acetic acid?

K_{a} = 1.8 \times 10^{- 5}

Q. In order to prepare a buffer solution of pH 5.74, sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1.0 M, the concentration of sodium acetate in the buffer is ______M. (Round off to the Nearest Integer).
[Given:

p K_{a}

(acetic acid) = 4.74]

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Acidic Buffer Action

Standard XII Chemistry

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A buffer solution of pH=5.74 is to be prepared using CH3COOH and CH3COONa. Find the concentration of sodium acetate to be added to 0.01 M solution of CH3COOH Ka(CH3COOH)=1.8×10−5 Take log(1.8)=0.26

The correct option is A 0.1 MpKa=−log(Ka)pKa=−log(1.8×10−5)=(5−0.26)pKa=4.74 pH=pKa+log[salt][acid]pH=pKa+log([CH3COONa][CH3COOH])5.74=4.74+log[CH3COONa]0.011=log[CH3COONa]0.01101=[CH3COONa]0.01[CH3COONa]=0.1 M

A buffer solution of $p H = 5.74$ is to be prepared using $C H_{3} C O O H$ and $C H_{3} C O O N a$ . Find the concentration of sodium acetate to be added to $0.01 M$ solution of $C H_{3} C O O H$
$K_{a} (C H_{3} C O O H) = 1.8 \times 10^{- 5}$
Take $l o g (1.8) = 0.26$