A bulb emits light of wavelength 4500A0. The bulb is rated as 150 watt and 8% of the energy is emitted as light. How many photons are emitted by the bulb per second?
A
27.2×1018
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B
2.72×1016
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C
27.5×104
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D
27.2×108
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Solution
The correct option is A27.2×1018 The energy of 1 photon is E=hcλ=6.626×10−34×3×1084500×10−10=4.42×10−19J
Total energy (in the form of light) emitted in 1 second is =150×8100=12J
The number of photons emitted is 124.42×10−19=27.2×1018.