According to the experiment of photoelectric effect, the number of electrons ejected from the metal surface is proportional to the intensity or brightness of light.
The threshold frequency ν0 for a metal is 7.0 × 1014 s−1. Calculate the kinetic energy of an electron emitted when radiation of frequency ν = 1.0 × 1015 s−1
1.99 x 10-19 J
2.99 x 1019 J
3.99 x 10-19 J
4.99 x 10-19 J
2 : 1
1 : 2
1.6 : 1
2.3 : 1
The kinetic energy of an electron is 4.55×10−25 J. The mass ofelectron is 9.1×10−31kg. Calculate velocity of the electron.
A Light of wavelength λ shines on a metal surface with intensity X, and the metal emits Y electrons per second of average energy Z. What will happen to Y and Z If X is doubled?
Y will be doubled and Z will become half.
Y will remain same and Z will be doubled.
Both Y and Z will be doubled.
Y will be doubled but Z will remain same.
If the threshold frequency of a metal for photoelectric effect is v0, then which of the following will not happen?
If the frequency of the incident radiation is v0, the kinetic energy of the electrons ejected is zero.
If the frequency of the incident radiation is v, the kinetic energy of the electrons ejected will be hv - hv0.
If the frequency is kept sameat v but intensity is increased, the number of electrons ejected will increase.
If the frequency of incident radiation is further increased, the number of photoelectrons ejected will increase.
According to Einstein photoelectric effect equation, the graph between the kinetic energy of photoelectron ejected and the frequency (ν) of incidented radiations is: