Given that,
Voltage V=220volt
Power P=150W
Now, the resistance of the bulb is
P=V2R
R=220×220150
R=322.67Ω
Now, the rms current through the bulb
P=Irms×Vrms
Irms=PVrms
Irms=150220
Irms=0.68A
Hence, the resistance is 322.67 Ω and the rms current is 0.68 A