Question

A bulb of power 40 W is used for 12.5 h each day for 30 days. Calculate the electrical energy consumed.

Answer 1

We know

Energy consumed = Power $\times$ times internal

$\Delta E=40\times 12.5\times \left(3600\right)\times 30J$

$\Delta E=\frac{5.4\times {10}^3}{3.6\times {10}^6}k\omega h=15k\omega h$

Energy consumed in $30$ days is $15k\omega h$