A bullet is fired from a gun. The force on the bullet is given by F = 600 - 2 × 105 t, where F is in Newton and t in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet
The correct option is (C) 0.9 Ns
The time when this force becomes zero
Time taken by the bullet to leave the barrel is 3 milliseconds.
Impulse = F.idt=(600−2×105t)dt
Now putting values of t in above equation
Hence, the impulse is 0.9 Ns.