Question

A bullet is fired from a gun the force on the bullet is given by $F=600-2\times {10}^{5}t$ where F is in newton and t in second. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet?

• A. $9Ns$
• B. $Zero$
• C. $0.9Ns$
• D. $1.8Ns$

Answer 1

The correct option is C $0.9Ns$

From given question

At F = 0

$600-2\times {10}^{5}t=0$

$t=3\times {10}^{-3}s$

$J=\int Fdt$

=$600t-[2\times {10}^5\times \frac{t^2}{2}]$

at $t=3\times {10}^{-3}$

$J=0.9Ns$

Hence [c] option is correct