A bullet is moving at a speed of 367m/s when it embeds into a lump of moist clay. The bullet penetrates for a distance of 0.0621m. Determine the acceleration of the bullet while moving into the clay. (Assume a uniform acceleration.)
A
1.08×106ms2
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B
−1.08×106ms2
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C
−1.08×108ms2
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D
−1.08×107ms2
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Solution
The correct option is B−1.08×106ms2 Here, initial velocity of bullet is u=367m/s and final velocity is v=0m/s.
Distance traveled by bullet is d=0.0621m
If a be the acceleration of bullet.
Using v2−u2=2ad
02−(367)2=2a(0.0621)
⟹a=−1.08×10−6m/s2
(negative sign indicates deceleration of bullet means it slows down).