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Question

A bullet of 10 g strikes a sand-bag at a speed of 103 ms1 and gets embedded after travelling 5 cm. Then the time taken by the bullet to come to rest is :

A
10 s
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B
102 s
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C
102 s
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D
104 s
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Solution

The correct option is D 104 s
v2=u2+2as
0=(103)2+2×a×(5×102)
a=107 m/s2

v=u+at
0=103107×t
t=104 s

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