A bullet of 5 g is fired from a pistol of 1.5 kg. If the recoil velocity of pistol is 1.5ms−1, what is the final momentum of the pistol?
A
10kgms−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.5kgms−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.5kgms−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.25kgms−1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D2.25kgms−1 Given, recoil velocity of the pistol, v=1.5ms−1 and mass of the pistol, m=1.5kg
Let 'p' be the final momentum of the pistol.
We know, p=m×v=1.5×1.5=2.25kgms−1
Therefore, final momentum of the pistol is 2.25kgms−1