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Question

A bullet of mass 20g is fired left to right with a velocity of 150m/s from a pistol of mass 2kg. What is the recoil velocity of the pistol?

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Solution

Given,

Mass of bullet = m1=20g=0.02kg

Mass of pistol = m2=2kg

Initial velocity of bullet = u1=0

Initial velocity of pistol = u2=0

Final velocity of bullet = v1=150ms1

Let final velocity of pistol = u2=0

By conservation of linear momentum, Initial momentum = Final momentum

m1u1+m2u2=m1v1+m2v2

0=0.02×150+2v2

v2=150ms1

Therefore, the pistol recoils with a velocity of 150 m/s towards the left.


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