A bullet of mass 20 g moving with a velocity of 100 m/s strikes a wooden block of mass 80 g and gets embedded into it. Calculate the velocity of the combined system.

10 ms^-1

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30 ms^-1

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20 ms^-1

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5 ms^-1

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Solution

The correct option is C
20 ms^-1

By applying law of conservation of momentum,

intial momentum of the system = final momentum of the system

$(0.020 \times 100) + (0.080 \times 0)$ = velocity of system after collision * (0.020 + 0.080 )
$\Rightarrow 2 = 0.1 \times v$

Velocity of system after impact = $20 \frac{m}{s}$ .

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A bullet of mass 20 g moving with a velocity of 100 m/s strikes a wooden block of mass 80 g and gets embedded into it. Calculate the velocity of the combined system.

The correct option is C 20 ms-1 By applying law of conservation of momentum, intial momentum of the system = final momentum of the system (0.020×100)+(0.080×0) = velocity of system after collision * (0.020 + 0.080 ) ⇒2=0.1×v Velocity of system after impact = 20ms.