A bullet of mass 50 g is moving with a velocity of 500 m/s. If it penetrates into a 10 cm still target and comes to rest, calculate the average retarding force offered by the target.

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Solution

Retardation, $a = \frac{v^{2} - u^{2}}{2 a} = \frac{0^{2} - 500^{2}}{2 \times 0.1} = 1250000 m / s^{2}$

So, average force, $F = 0.05 \times 1250000 = 62500 N$

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A bullet of mass 50 g is moving with a velocity of 500 m/s. If it penetrates into a 10 cm still target and comes to rest, calculate the average retarding force offered by the target.

Retardation, a=v2−u22a=02−50022×0.1=1250000 m/s2 So, average force, F=0.05×1250000=62500 N

Retardation, $a = \frac{v^{2} - u^{2}}{2 a} = \frac{0^{2} - 500^{2}}{2 \times 0.1} = 1250000 m / s^{2}$

So, average force, $F = 0.05 \times 1250000 = 62500 N$