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Question

A bullet of mass 'a'and velocity 'b' is fired into a large block of wood of mass 'c'. The bullet gets embedded into the block of wood. The final velocity of the system is


A

ba+b×c

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B

a+bc×a

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C

aa+c×b

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D

a+ca×b

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Solution

The correct option is C

aa+c×b


Hint: Conservation of Momentum states that the initial and final momentum of the system remains the same if there is no external force on the system.

Step 1: Given data

Mass of bullet m1 =a

Velocity of bullet v1=b

Mass of block of wood m2 =c

Step 2: Concept used

Conservation of Momentum

Step 3: Conservation of momentum defined

According to the conservation of momentum, the quantity called momentum that characterizes motion never changes in an isolated collection of objects; that is, the total momentum of a system remains constant.

m1v1+m2v2=m1+m2v

Step 4: Finding the final velocity of the system

m1v1+m2v2=m1+m2va×b+c×0=a+cvv=aa+cb

Hence, option C is correct.


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