A bullets moving with a velocity of 200m/s strikes a wooden block and pierces up to 10 cm into it. Calculate the magnitude of retardation of the bullet, while piercing the wooden block, assuming the retardation to be uniform. What time is taken by the bullets for piercing through the wooden block?

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Solution

Dear Student

$u = 200 m / s v = 0 s = 10 c m = 0.1 m v^{2} = u^{2} + 2 a s u^{2} = - 2 a s a = - \frac{200 \times 200}{2 \times 0.1} = - 200000 m / s^{2} N e g a t i v e s i g n b e c a u s e r e t a r d a t i o n v = u + a t u = - a t t = - \frac{u}{a} = \frac{200}{200000} = 0.001 s$

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A bullets moving with a velocity of 200m/s strikes a wooden block and pierces up to 10 cm into it. Calculate the magnitude of retardation of the bullet, while piercing the wooden block, assuming the retardation to be uniform. What time is taken by the bullets for piercing through the wooden block?

Dear Student u=200m/sv=0s=10 cm = 0.1 mv2=u2+2asu2=-2asa=-200×2002×0.1=-200000 m/s2Negative sign because retardationv =u +atu =-att =-ua=200200000=0.001s Regards

Dear Student

$u = 200 m / s v = 0 s = 10 c m = 0.1 m v^{2} = u^{2} + 2 a s u^{2} = - 2 a s a = - \frac{200 \times 200}{2 \times 0.1} = - 200000 m / s^{2} N e g a t i v e s i g n b e c a u s e r e t a r d a t i o n v = u + a t u = - a t t = - \frac{u}{a} = \frac{200}{200000} = 0.001 s$

Regards