A burner supplies heat energy at a rate of $20 J s^{- 1}$ . Find the specific heat capacity of a solid of mass $25 g$ , if its temperature rises by $80 ° C$ in one minute.

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Solution

Step 1: Information
Given
mass $(m) = 25 g$
Heat supplied $= 20 J s^{- 1}$
Time is one minute
$θ_{R} = 80 ° C$
Find:
The specific heat capacity of solid.
Step 2: Calculating the specific heat capacity
Heat supply $20 \times 60 = 1200 J$
Heat supplied is given as $m c θ_{R}$
$1200 = 25 \times c \times 80 c = \frac{1200}{25 \times 80} c = 0.6 J g^{- 1} ° C^{- 1}$
Hence the specific heat capacity is $0.6 J g^{- 1} ° C^{- 1}$ .

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