A burner supplies heat energy at the rate of 434 J-s for 60 s when 40 g of ice at 0 deg-c changes to water at 75 deg-c-Calculate the latent heat of ice-

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Standard VIII

Physics

Scientific Method and Measurements

A burner supp...

Question

A burner supplies heat energy at the rate of 434 J/s for 60 s when 40 g of ice at 0°c changes to water at 75°c.Calculate the latent heat of ice?

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Solution

Dear Student

Heat energy absorbed when 40 g of ice at 0 degree celsius changes into 40 g of water at 0 degree celsius.

H₁= mL = 40 L
Heat energy absorbed when 40 g of water at 0 degree celsius changes into 40 g of water at 75 degree celsius.

H₂= mCT = 40(4.2 J/gK)(75)= 12600

$R a t e o f h e a t e n e r g y s u p p l i e d p e r s e c = \frac{H e a t s u p p l i e d}{t i m e t a k e n} 434 J / s = \frac{40 L + 12600}{60} 40 L = 26040 - 12600 = 13440 L = 336 J / g K$

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