A bus decreases its speed from 80 km/h to 60 km/h in 5 seconds. Find the acceleration of the bus.

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Solution

Step 1: Given data
Initial velocity, $u = 80 k m h^{- 1} = 22.2 m s^{- 1}$
Final velocity, $v = 60 k m h^{- 1} = 16.7 m s^{- 1}$
Time, $t = 5 s$
Step 2: Formula used
$v = u + a t$
Where “a” is the acceleration.
Step 3: Determine the acceleration
Using the first equation of motion,
$v = u + a t 16.7 = 22.2 + a (5) a = \frac{16.7 - 22.2}{5} a = - 1.1 m s^{- 2}$
The value is negative as the bus is decelerating
Therefore, the acceleration of the bus is $- 1.1 m s^{- 2}$

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