a bus starting from rest attains a speed of 36 km per hour in 5 seconds calculate acceleration and distance travel by bus during this duration

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Solution

Dear Student,

$initial velocity, u = 0 final velocity, v = 36 km / h v = 36 \times \frac{5}{18} m / s = 10 m / s time, t = 5 s v = u + at 10 = 0 + a \times 5 a = 2 m / s^{2} v^{2} - u^{2} = 2 as 10^{2} - 0^{2} = 2 \times 2 s s = \frac{100}{4} = 25 m$

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a bus starting from rest attains a speed of 36 km per hour in 5 seconds calculate acceleration and distance travel by bus during this duration

Dear Student, initial velocity, u=0final velocity, v=36 km/hv=36×518 m/s=10 m/stime, t=5 sv=u+at10=0+a×5a=2 m/s2v2-u2=2as102-02=2×2ss=1004=25 m

Dear Student,

$initial velocity, u = 0 final velocity, v = 36 km / h v = 36 \times \frac{5}{18} m / s = 10 m / s time, t = 5 s v = u + at 10 = 0 + a \times 5 a = 2 m / s^{2} v^{2} - u^{2} = 2 as 10^{2} - 0^{2} = 2 \times 2 s s = \frac{100}{4} = 25 m$