Question

A bus starting from rest moves with a uniform acceleration of 0.1 ms^-2 for 2 minutes. Find the distance traveled.

Answer 1

Step 1: Given data:

1. The initial velocity (u) of the bus is zero as it starts from rest.
2. The acceleration of the bus is 0.1 m/s².
3. Time taken by the bus is $2\mathrm{minutes}=120\mathrm{s}$.

Step 2: Finding the distance traveled:

By using the 2nd equation of motion;

$S=\mathrm{ut}+\frac{1}{2}{\mathrm{at}}^2$

Where, S is the distance traveled, u is initial velocity, a is a constant acceleration, and t is time.

$$\begin{gathered} \Rightarrow \mathrm{S}=0+\frac{1}{2}(0.1){\left(120\right)}^2 \\ \Rightarrow \mathrm{S}=720\mathrm{m} \end{gathered}$$

Hence, the distance traveled at the end of 2 minutes is 720 m.