Question

A bus starts from city X. The number of women in the bus is half the number of men. In the city Y, $10$ men left the bus and five women boarded in to it. Now, number of men and women becomes equal. In the beginning, how many passengers entered the bus?

• A. $15$
• B. $30$
• C. $36$
• D. $45$

Answer 1

The correct option is D $45$

Let the number of men $=x$ and number of women$=\frac{1}{2}x$
According to problem,
$x-10=\frac{1}{2}x+5$
$x-\frac{1}{2}x=5+10$
$\frac{x}{2}=15$
$x=30$
Hence, no. of men$=30$
No. of women$=\frac{30}{2}=15$
Total no. of passengers that entered the bus $=15+30=45$