Dear student. GIVEN : Initial velocity (u = 0 Final velocity (v)= 36 kmph Time (t )= 10 min = 1/6 hr Acceleration (a )= ? by using 1st equation of motion, we get v=u+at 36 = 0+a ×1/6 a = 36×6 a = 216 km/hr^2 hence the acceleration of the bus is 216 km/hr^2