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Question

A bus starts moving with an acceleration of 2m/s2. A cyclist 96m behind the bus starts simultaneously towards the bus at 20m/s. After what time will he be able to overtake the bus?


A

4s

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B

8s

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C

12s

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D

16s

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Solution

The correct option is B

8s


In t seconds bus travels a distance of x meters and boy travels (96+ x) meters

for bus,

x=at22=2×t22=t2.....................................(1)

for boy,

x+96 = vt

x+96 = 20t ......................................................(2)

using (1) and (2),

t2 - 20t + 96 = 0

we get t = 12 and 8,

Boy will catch the bus at t = 8 seconds.


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