A bus starts moving with an acceleration of 2m/s2. A cyclist 96m behind the bus starts simultaneously towards the bus at 20m/s. After what time will he be able to overtake the bus?
8s
In t seconds bus travels a distance of x meters and boy travels (96+ x) meters
for bus,
x=at22=2×t22=t2.....................................(1)
for boy,
x+96 = vt
x+96 = 20t ......................................................(2)
using (1) and (2),
t2 - 20t + 96 = 0
we get t = 12 and 8,
Boy will catch the bus at t = 8 seconds.