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Question

(a) Calculate the percentage of sodium in sodium aluminium fluoride (Na3AIF6) correct to the nearest whole number. (F = 19; Na = 23; Al = 27)
(b) 560 ml of carbon monoxide is mixed with 500 ml of oxygen and ignited. The chemical equation for the reaction is as follows:
2CO + O2 2CO2
Calculate the volume of oxygen used and carbon dioxide formed in the above reaction.

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Solution

(a) Molar mass of sodium aluminium fluoride = 3(23) + 27 + 6(19) = 210 g
Mass of sodium in sodium aluminium fluoride = 69 g
Percentage of Na =Mass of Na in compoundMolecular mass of Na3AlF6×100=69210×100=32.85 33%

(b) For two moles of CO, one mole of O2 is used.
So, according to the Avogadro's law:
Volume of oxygen used by 560 mL of CO = 5602mL=280 ml
Also, number of moles or volume of CO used in reaction is equal to the number of moles or volume of CO2 formed.
Volume of CO2 formed = 560 mL


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