A can contains a mixture of two liquids A and B in the ratio 7:5. When 9 litres of mixture is drawn off and the can is filled with B, the ratio of A and B becomes 7:9. Litres of liquid A contained by the can initially was:
A
10
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B
20
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C
21
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D
25
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E
None of these
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Solution
The correct option is C 21 Let the quantity initially of liquid A be 7x litre ∴ Let the quantity initially of liquid B be 5x litre Quantity of A after 9 litres mixture drawn =7x−214=28x−214litres Quantity of B after 9 litres mixture drawn and adding 9 litres of B =5x+214=20x+214 ∴(28x−21)4:20x+214=79 ⇒(252−140)x=189+147 ⇒x=336112=3 The required quantity of A = 7x = 21 litres.