Question

A can do a piece of work in 15 days. 13 is 50% more efficient than A. B can finish it in

(a) 10 days

(b) $7\frac{1}{2}$ days

(c) 12 days

(d) $10\frac{1}{2}$days

Answer 1

A's 1 day's work $=\frac{1}{15}$

Then B's 1 day's work $=\frac{1}{10}\times \frac{100+50}{100}$

$=\frac{1}{15}\times \frac{150}{100}=\frac{1}{10}$

$\therefore$ B will finish the work in =10 days