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Question

A can do a piece of work in 15 days. B is 50% more efficient than A. B can finish the total work in
(a) 10 days
(b) 712 days
(c) 12 days
(d) 1012 days

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Solution

Correct option is (a). 10 days
Amount of work done by A in one day =115 units.

Since, B is 50% more efficient than A, therefore,

Amount of work done by B in one day =115+12×115=115×32=110 units.

Thus, time taken to complete the total work =1÷110

=10 days


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