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Question

# A can do a piece of work in 25 days, which B alone can do in 20 days. A started the work and was joined by B after 10 days. The work lasted for(a) 1212 days(b) 15 days(c) 1623 days(d) 14 days

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Solution

## A can do the piece of work in 25 days.The part of the work done by A in 1 day=125B can do the same work in 20 days.The part of the work done by B in 1 day =120Since, A worked as alone 10 days.So, the part of the work done by A in 10 days =1025=25⇒ The remaining work =1−25=35---(1)The part of the work done by A+B =125+120=4+5100=9100Hence, The part of the work done by A+B=9100Since, the remaining part of the work is 35⇒ Time taken to finish the remaining work if they work together =35÷9100=35×1009=10015=61015=623So they will finish the remaining work in 623 days.Here A already worked in 10 days.So, Total number of days to finish the work =(10+623) days=(10+6+23) days=1623 daysHence, Option C is correct.

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