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Question
A can do a piece of work in 30 days, B can do in 45 days and C can do same work alone in 60 days. If on the first day A worked alone and on the second day A and B worked together and on the third day A and C worked together. If they repeat the cycle as follows then in how many days total work can be completed?
A can do a piece of work in 30 days, B can do in 45 days and C can do same work alone in 60 days. If on the first day A worked alone and on the second day A and B worked together and on the third day A and C worked together. If they repeat the cycle as follows then in how many days total work can be completed?
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Solution
The correct option is C 21 5/6 Days
First day = 1/30; Second day = 1/30+1/45; Third day = 1/30+1/60
3 days work = 3/30+1/45+1/60 = 25/180
3*7 = 21 days work = 175/180
Now 1/36 work is left which can be completed by A alone
1/36*30 = 5/6
21+5/6 = 21 5/6 Days
First day = 1/30; Second day = 1/30+1/45; Third day = 1/30+1/60
3 days work = 3/30+1/45+1/60 = 25/180
3*7 = 21 days work = 175/180
Now 1/36 work is left which can be completed by A alone
1/36*30 = 5/6
21+5/6 = 21 5/6 Days
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