Question

A candidate scored $25$% marks in an examination and failed by $30$ marks, while another candidate who scored $50$% marks got $20$ marks more than the minimum pass marks. Find the maximum marks and minimum pass marks.

Answer 1

Solution:-

Let maximum marks be $x$

Minimum marks to pass $=25\%$ of $x+30=\frac{x}{4}+30$

Now according to question,

$\frac{x}{4}+30=\frac{x}{2}-20$

$\frac{x}{2}-\frac{x}{4}=30+20$

$\Rightarrow x=50\times 4=200$

Hence the maximum marks to be obtained are $200$.

Now, minimum passing marks $=\frac{200}{4}+30=80$

Hence the maximum marks to be obtained are $200$ and the minimum passing marks are $80$.