A cannon ball of mass $5$ kg is discharged horizontally with a velocity of $500 m / s$ . If the cannon be free to move on the horizontal ground, what is the velocity with which it recoils? Mass of the cannon is $100$ kg.

15m/s

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25m/s

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35m/s

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45m/s

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Solution

The correct option is B 25m/s
Given : $M_{b a l l} = 5 k g$ $v = 500 m / s$ $M_{c a n n o n} = 100 k g$
Recoil velocity of cannon $V = \frac{M_{b a l l} \times v}{M_{c a n n o n}}$
$⟹ V = \frac{5 \times 500}{100} = 25 m / s$

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A cannon ball of mass 5kg is discharged horizontally with a velocity of 500m/s. If the cannon be free to move on the horizontal ground, what is the velocity with which it recoils? Mass of the cannon is 100kg.

The correct option is B 25m/sGiven : Mball=5 kg v=500 m/s Mcannon=100 kgRecoil velocity of cannon V=Mball×vMcannon⟹ V=5×500100=25 m/s

A cannon ball of mass $5$ kg is discharged horizontally with a velocity of $500 m / s$ . If the cannon be free to move on the horizontal ground, what is the velocity with which it recoils? Mass of the cannon is $100$ kg.

The correct option is B 25m/s
Given : $M_{b a l l} = 5 k g$ $v = 500 m / s$ $M_{c a n n o n} = 100 k g$
Recoil velocity of cannon $V = \frac{M_{b a l l} \times v}{M_{c a n n o n}}$
$⟹ V = \frac{5 \times 500}{100} = 25 m / s$