Question

A capacitor of 2 $\mu$F draws a current of 4mA when connected across an a.c. of 300Hz. The voltage drop across capacitor is

• A. 1.06V
• B. 1.5V
• C. 2.1V
• D. 6.6V

Answer 1

The correct option is A 1.06V

Capacitive reactance $X_C=\frac{1}{\omega C}$

$\therefore$ $X_C=\frac{1}{2\pi fC}$

$X_C=\frac{1}{2\pi \times 300\times 2\times {10}^{-6}}$

Voltage drop across capacitor

$V_C=i\times X_C$

$V_C=4\times {10}^{-3}\times \frac{1}{2\pi \times 300\times 2\times {10}^{-6}}$

$V_C=1.06V$