Question

A capacitor of $25\mu F$, inductor of $0.1H$ and resistor of resistance $25\Omega$ are connected in series with an $A.C$. source of $e.m.f$. $e=310\sin \left(314t\right)volt$.What is the

• A. Reactance
• B. Impedance and the current of the circuit?
• C. Phase angle between current and applied e.m.f.?
• D. Expression for instantaneous value of current?

Answer 1

Answer: (A)

Reactance

Given,

$C=25\mu F$

$L=0.1H$

$R=25\Omega$

$E=310sin\left(314t\right)volt$

If inductance and capacitor are connected in series then

Reactance$=|X_C-X_L|=|\frac{1}{\omega C}-\omega L|$

Substitute all value in above equation

$|\frac{1}{314\times 25\times {10}^{-6}}-314\times 0.1|=|\frac{20000}{157}-31.4|=|127.39-31.4|=96\Omega$