An inductor and a resistor in series are connected to an A.C. supply of variable frequency. As the frequency of the source is increased, the phase angle between current and the potential difference across L will:

First increase and then decrease

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First decrease and then increase

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Go on decreasing

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Go on increasing

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Solution

The correct option is A Go on increasing
Let the frequency of the source be $f$ .
Inductive reactance $X_{L} = w L = 2 π f L$
Resistance of the resistor $= R$
Using $tan ϕ = \frac{X_{L}}{R}$
$⟹ tan ϕ = \frac{2 π f L}{R}$
With increase in frequency, $tan ϕ$ will increases and so $ϕ$ wil increase.
So, the phase angle between current and potential difference will increases on increasing the frequency.

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