1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A capacitor of capacitance C, charged to potential difference V is connected to another capacitor of capacitance 3C, charged to potential difference 3V as shown in the figure. The final charges on capacitor of capacitance C and 3C are respectively

A
5CV2, 15CV2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
15CV2, 5CV2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
5CV2, 10CV2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
5CV2, 15CV2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

The correct option is A 5CV2, 15CV2Initially charges on the capacitors are calculated using Q=CV as shown in figure below. From the law of conservation of charge, Initial charge (qi)=Final charge(qf) Let the final potential across both the capacitors be E. So, CV+9CV=CE+3CE Finally: ⇒E=10V4=5V2 So, the final charge on C qC=5V2×C=5CV2 Charge on 3C, q3C=5V2×3C=15CV2 Hence, option (a) is correct answer.

Suggest Corrections
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program