Potential and Potential Difference
Trending Questions
Q. A parallel-plate capacitor has plates of area 200 cm2 and separation between the plates 1 mm. The potential difference developed if a charge of 1 nC(i.e.1×10−9C) is given to the capacitor is something, then if the plate separation is now increased to 2 mm, what will be the new potential difference?
Q. If 100 volts of potential difference is applied between a and b in the circuit of given figure. Find the potential difference (in V) between c and d.

Q. An uncharged parallel-plate capacitor having a dielectric of dielectric constant K is connected to a similar air cored parallel-plate capacitor charged to a potential V0. The two share the charge and the common potential becomes V. The dielectric constant K is
- V0V−1
- V0V+1
- VV0−1
- VV0+1
Q. A hemispherical earth plate is buried into the earth. Find the potential difference between the feet of a man standing on ground as shown in figure. Current through earth plate is I. Conductivity of earth is [δ=10−3π, I=1A] (up to two decimal places)


Q. A parallel-plate capacitor has plates of area A and separation d and is charged to a potential difference V. The charging battery is then disconnected and the plates are pulled apart until their separation is 2d. What is the work required to separate the plates?
- 3∈0AV22d
- 2∈0AV2d
- ∈0AV2d
- ∈0AV22d
Q. The work done in increasing the potential of a capacitor from V volt to 2V volt is W. Then, the work done in increasing the potential of the same capacitor from 2V volt to 4V volt will be
- W
- 2 W
- 4 W
- 8 W
Q. The work done on the capacitor is QV but the energy stored in the capacitor is 1/2QV. Why? By neglecting the resistance.
Q. A 10 μF capacitor charged to 20 V is connected across a 15 V battery through a switch such that positive terminal of battery is connected to negative charged plate of capacitor. When switch is closed, work done by battery of 15 V in long time will be
- 2250 μJ
- −3000 μJ
- 30000 μJ
- 5250 μJ
Q. Two metallic spheres of radii 1 cm and 3 cm are given charges of −1×10−2C and 5×10−2C respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is
- 2×10−2C
- 3×10−2C
- 4×10−2C
- 1×10−2C
Q.
A : स्थिरवैद्युत क्षेत्र रेखाऐं किसी अचालक पृष्ठ पर सदैव लम्बवत् होती हैं।
R : Inside a conductor, electrostatic potential does not vary.
R : किसी चालक के अन्दर, स्थिरवैद्युत विभव परिवर्तित नहीं होता है।
This section contains 1 Assertion-Reason type question, which has 4 choices (a), (b), (c) and (d) out of which ONLY ONE is correct.
इस खण्ड में 1 कथन-कारण प्रकार का प्रश्न है, जिसमें 4 विकल्प (a), (b), (c) तथा (d) दिये गये हैं, जिनमें से केवल एक सही है।
A : Electrostatic field lines are always perpendicular on a non-conducting surface.A : स्थिरवैद्युत क्षेत्र रेखाऐं किसी अचालक पृष्ठ पर सदैव लम्बवत् होती हैं।
R : Inside a conductor, electrostatic potential does not vary.
R : किसी चालक के अन्दर, स्थिरवैद्युत विभव परिवर्तित नहीं होता है।
- Both (A) and (R) are true and (R) is the correct explanation of (A)
(A) तथा (R) दोनों सही हैं तथा (R), (A) का सही स्पष्टीकरण है - Both (A) and (R) are true but (R) is not the correct explanation of (A)
(A) तथा (R) दोनों सही हैं लेकिन (R), (A) का सही स्पष्टीकरण नहीं है - (A) is true but (R) is false
(A) सही है लेकिन (R) गलत है - (A) is false but (R) is true
(A) गलत है लेकिन (R) सही है