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Question

A parallel plates capacitor is charged and the charging battery is then disconnected. If the plates of the capacitor are moved farther apart by means of insulating handles, then

A
the charge on the capacitor increases
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B
the voltage across the plates increases
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C
the capacitance increases
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D
the electrostatic energy stored in the capacitor increases.
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Solution

The correct option is D the electrostatic energy stored in the capacitor increases.
Charge on plate is q
Capacitance of parallel plate capacitor is
C=ϵ0Ad
we know that
q=CV

V=qC
Potential energy stored in capacitor is U=q22C

Given that distance between capacitors is increased to d
Charge on plate remains q as charging battery is removed. The charge on the capacitor remains constant.

New capacitance
C=ϵ0Ad<C

Capacitance decreases as the plates of capacitor are moved farther apart.
The options (a) and (c) are incorrect.

Potential across the plates V=qC>qC
Hence V increases.
Option (b) is correct.

Energy stored in the capacitor U=12q2C>12q2C
U increases.
Option (d) is correct.






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