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Standard XII

Physics

Turns Ratio

A capcacitor ...

Question

A capcacitor of capacity 6μF and intial charge 160μC is connected with a key S and different resistors as shown in figure. Point M is earthed. If key is closed at t = 0; then the current through resistance R (=1Ω) at 6 = 16μs is

$\frac{10}{3 e} A$

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$\frac{10}{e} A$

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$\frac{20}{3 e} A$

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None of the above

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Solution

The correct option is C
$\frac{20}{3 e} A$

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Similar questions

Q. A capacitor of capacity

6 μ F

and initial charge

160 μ C

is connected with a key

s

and resistance as shown in figure. Point M is earthed. If key is closed at

t = 0

; then the current through resistances

R_{1}

and

R_{2}

t = 16 μ s

are

Q. A capacitor of capacity

6 μ F

and initial charge

160 μ C

in connected with key S and resistance as shown in figure. Point

M

is earthed. If key is closed at

t = 0

, then the current through resistance

(R = 1 Ω

) at

(t = 16 μ s)

\frac{4 n}{3 e} A

, then find

n

Q. A capacitor of capacitance

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and initial charge

192 μ C

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S

and resistance as shown in figure. Point

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, at

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Q. Two resistors of

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Q. An inductor of inductance

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and a resistor of resistance

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are connected senes to a battery of EMF

20

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in a circuit as shown.The key

K_{1}

been kept closed for a long time. Then at

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K_{1}

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A capcacitor of capacity 6μF and intial charge 160μC is connected with a key S and different resistors as shown in figure. Point M is earthed. If key is closed at t = 0; then the current through resistance R (=1Ω) at 6 = 16μs is

The correct option is C 203eA

The correct option is C
$\frac{20}{3 e} A$