Question

A capillary tube of radius $R$ is immersed in the water and water rises into the height $H$. Mass of water in capillary tube is $M$. if the radius of the tube is doubled, mass of water that will rise in capillary tube will be:

• A. $2M$
• B. $M$
• C. $\frac{M}{2}$
• D. $4M$

Answer 1

The correct option is A $2M$

Since, $Radiusofcapillary\propto \frac{1}{Height}$

$\frac{R_1}{R_2}=\frac{H_2}{H_1}$

$\frac{1}{2}=\frac{H_2}{H_1}$

$H_2=\frac{H_1}{2}$

So,

Volume $=\pi \left({2R_1}^2\right)\frac{H_1}{2}=2\pi {R_1}^2{H}_1$

$V_{final}=2V_{initial}$

So, mass will also get doubled.