Let h be the height through which the liquid rises in the capillary tube of radius r
h=2S cos θr ρ g
Mass of the water in the first tube is
m=π r2hρ =π r2×(2S cos θr ρ g)×ρ=2π r.S cos θg
Hence, m∝r
Let mass of water in capillary tube of radius 2r be m′, then
m′m=r′r=2rr=2
m′=2m=2×5 g=10 g