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Question

A car accelerates with an acceleration of 2 m/s2 for 20 s from rest on a straight path. Then it decelerates with 1 m/s2 until its velocity becomes zero. The total distance covered by the car is -

A
1400 m
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B
1300 m
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C
1200 m
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D
1100 m
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Solution

The correct option is C 1200 m
For first 20 s when car is accelerated:

s1=u1t1+12a1t21

s1=0×20+12×2×202=400 m

Also,

v1=u1+a1t1=0+2×20=40 m/s

When car is decelerated to rest :

v22u22=2a2s2

02402=2(1)s2

s2=800 m

So, total distance,

s=s1+s2=400+800=1200 m

Hence, option (C) is the correct answer.

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