A car acquires a velocity of $72 k m h^{- 1}$ in 2 s starting from rest. Calculate the average velocity

10 m s^{- 1}

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5 m s^{- 1}

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20 m s^{- 1}

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72 k m h^{- 1}

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Solution

The correct option is A $10 m s^{- 1}$
Average Velocity Equation
$v_{a} = \frac{(v + v_{0})}{2}$
Where: $v_{a} =$ average velocity
$v_{0}$ = initial velocity
$v$ = final velocity
velocity=72 km/h = $72000 / 3600$ m/s=20m/s
$V_{a} = \frac{(0 + 20)}{2} = 10 m / s$

Answer (A) $10 m s^{- 1}$

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