Question

A car covers a distance of 250 m in 6 seconds. If the acceleration of the car is $6m{s}^{-2}$. Find the final velocity of the car.

• A. $79.66m{s}^{-1}$
• B. $59.66m{s}^{-1}$
• C. $69.66m{s}^{-1}$
• D. $49.66m{s}^{-1}$

Answer 1

The correct option is B $59.66m{s}^{-1}$

Given,
distance covered, s = 250 m,
time taken, t = 6 s
acceleration, a = $6m{s}^{-2}$

Let the initial velocity of the car be u and final velocity be v.
From the second equation of motion,
$s=ut+\frac{1}{2}\times {at}^2$
$250=u\times 6+\frac{1}{2}\times {6\times 6}^2$
$\Rightarrow u=23.66m{s}^{-1}$
From the first equation of motion,
v = u + at
$\Rightarrow$$v=23.66+6\times 6$ = $59.66m{s}^{-1}$
$\therefore$The final velocity of the car is $59.66m{s}^{-1}$