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Question

A car covers four successive 6km stretches at speeds of 25kmph, 50kmph, 75kmph and 150kmph respectively. Its average speed over this distance is:

A
25kmph
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B
50kmph
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C
75kmph
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D
150kmph
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Solution

The correct option is B 50kmph
Average speed if distance is same =4×abcd/[abc+bcd+abd+acd] where a,b,c,d are the different speeds at same distance.

Now, according to the question,
Average speed =4×25×50×75×150/[(25×50×75)+(50×75×150)+(25×50×150)+(25×75×150)]
=50

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