A car has to cover the distance $60 k m$ . If half of the total time it travels with speed $80 k m / h$ and in rest half time its speed becomes $40 k m / h$ , the average speed of car will be:

60 k m / h

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80 k m / h

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120 k m / h

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180 k m / h

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Solution

The correct option is A $60 k m / h$
Given,
$d = 60 k m$
Let's consider the total time taken to cover the distance is $t$ .
If half of the total time traveled with speed $80 k m / h$ ,
$d_{1} = 80 \times \frac{t}{2} = 40 t$
Rest half time is covered with speed $40 k m / h$ ,
$d_{2} = 40 \times \frac{t}{2} = 20 t$
The average speed of the car is Total distance covered by the car divided total time,
$v_{a v g} = \frac{d_{1} + d_{2}}{t}$
$v_{a v g} = \frac{40 t + 20 t}{t} = \frac{60 t}{t}$
$v_{a v g} = 60 k m / h$
The correct option is A.

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A car has to cover the distance 60 km. If half of the total time it travels with speed 80 km/h and in rest half time its speed becomes 40 km/h, the average speed of car will be:

A car has to cover the distance $60 k m$ . If half of the total time it travels with speed $80 k m / h$ and in rest half time its speed becomes $40 k m / h$ , the average speed of car will be: