A car has to cover the distance of 60 km-hr-if half of the total time it travels with speed nbsp- 80 km-hr and rest in half time its speed becomes 40 km-hr the nbsp-avg speed of the car is nbsp-

Dear Student , Here in this case as we know that , Average #160;velocity=Total #160;distanceTotal #160;time #160;takenNow #160;, #160;again #160;a ...

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Standard XII

Physics

Instantaneous Velocity

a car has to ...

Question

a car has to cover the distance of 60 km/hr.if half of the total time it travels with speed 80 km/hr and rest in half time its speed becomes 40 km/hr the avg speed of the car is

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Solution

Dear Student ,
Here in this case as we know that ,
$A v e r a g e v e l o c i t y = \frac{T o t a l d i s \tan c e}{T o t a l t i m e t a k e n} N o w, a g a i n a v e r a g e v e l o c i t y i s, V_{a v g} = \frac{v_{1} + v_{2}}{2} N o w, h e r e v_{1} = 80 k m / h r a n d v_{2} = 40 k m / h r S o, V_{a v g} = \frac{v_{1} + v_{2}}{2} = \frac{80 + 40}{2} = \frac{120}{2} = 60 k m / h r$
Regards

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a car has to cover the distance of 60 km/hr.if half of the total time it travels with speed 80 km/hr and rest in half time its speed becomes 40 km/hr the avg speed of the car is

Dear Student , Here in this case as we know that , Average velocity=Total distanceTotal time takenNow , again average velocity is , Vavg=v1+v22Now , here v1=80 km/hr and v2=40 km/hrSo , Vavg=v1+v22=80+402=1202=60 km/hr Regards