wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A car is moving in a circular path of radius 2 m. Calculate both the distance and the magnitude of the displacement of the car after
i) one complete revolution
ii) one-half revolution
iii) one-fourth revolution.
What can you conclude about the relationship between distance and displacement.

Open in App
Solution

Radius R = 2 m i) Distance = 2πR = 2π × 2 = 4π m Displacement = Zero, (displacement is the shortest distance between the starting and finishing points. Here car reached at starting point. So displacement Zero.) ii) Distance = 2πR/2 = 2π × 2 / 2 = 2π m Displacement = 2R = 2×2 = 4 m. (Here diameter the displacement) iii) Distance = 2πR/4 = 2π × 2 /4 = 4π/4 = π m Displacement =√(2^2 + 2^2) = 2√2 m There is no relationship between distance and displacement. ​​​​​

flag
Suggest Corrections
thumbs-up
9
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Distance and Displacement
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon