A car is moving with a constant speed of $50 k m / h r$ . Time taken $t$ to travel $200 k m$ is

$t = 2 h$

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$t = 5 h$

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$t = 6 h$

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$t = 4 h$

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Solution

The correct option is D
$t = 4 h$

Given, speed $u$ = $50 k m / h r$

Distance $s$ = $200 k m$

We know $s$ = $u t + \frac{1}{2} a t^{2}$ where $a$ = accelaration. In the above question accelaration is zero.

$\Rightarrow 200$ = $50 \times t$

$t = 4 h$

Suggest Corrections

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